A fair coin is tossed 3 times. What is the probability that you will have a H on the first toss AND a T on the last toss?

Answer 1

A fair coin is tossed 3 times. What is the probability that you will have a H on the first toss AND a T on the last toss?

Find the probability mathematically

(first toss) * (second toss) * (third toss):

(1/2) * (1) * (1/2) = (1/4)

There are only 2*2*2 = 8 possibilities,so let's list them:

first second third

T T T

T T H

T H T

T H H

H T T ***

H T H

H H T ***

H H H

(Note: If T=0 and H=1. this is 000 to 111 in binary)

Probability = (number of successful outcomes) / (number of possible outcomes)

P = 2 / 8 = 1/4