Simplify the following expression: 3sin2θ+4cos2θ

Question

Simplify the following expression: 3sin2θ+4cos2θ

7

1+cos2θ

cos2θ

3

−sin2θ

1

3+cos2θ

Answer 1

If we understand the meaning of "simplify" to be "rewrite with as few symbols possible", then this given expression is in simplest form.

Answer 2

3sin2θ+4cos2θ

3 ( 2 sin cos ) + 4 ( cos ^2 - sin ^2)

6 sin cos + 4 cos ^2 - 4 sin ^2

6 sin ( sqrt( 1 - sin^2)) + 4 (1 - sin^2) - 4 sin ^2

6 * sin * sqrt (1 - sin^2)) + 4 - 8 sin^2