Patrick B. answered 03/21/20
Math and computer tutor/teacher
Parts a-b:
Then the discriminant must be zero
A=3 vB = -6 C=p
0 = B^2 - 4ac = 36 - 4(3)(p) = 36 - 12p
p=3
Parts C-f:
b/(2a) = 6/6 = 1
3(1)^2 + -6(1) + 3 = 3-6+3 =0
the vertex is (1,0)=(h,k)
y = C(x-1)^2
per the original function f(0) = 3, so
3 = C(0-1)^2
3 = C(-1)^2
3=C(1)
C = 3
So the function is y = f(x) = 3(x-1)^2
Note that 3x^2 - 6x + 3 = 3(x^2 - 2x + 1) = 3(x-1)^2