If A is in invertible, then there is a matrix A-1 such that AA-1=A-1A=I. So consider -A-1.
(-A)(-A-1)=(-1)(-1)AA-1=AA-1=I, and (-A-1)(-A)=(-1)(-1)A-1A=A-1A=I.
So, we have shown that (-A)-1=-A-1. Therefore, -A is invertible.
Dorsa R.
asked 03/15/20If A is in invertible, then there is a matrix A-1 such that AA-1=A-1A=I. So consider -A-1.
(-A)(-A-1)=(-1)(-1)AA-1=AA-1=I, and (-A-1)(-A)=(-1)(-1)A-1A=A-1A=I.
So, we have shown that (-A)-1=-A-1. Therefore, -A is invertible.
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