(CLOSED) Chisom A. answered 03/12/20
Precalculus pro
x(t) = -3t; y(t) = -8 + 2t
Method 1:
Make the parameter t the subject of the x component equation,
x = -3t
t = -x/3
Then, substitute in the y(t) equation and solve for x:
y = -8 + 2(-x/3)
y = -8 - 2x/3
y + 8 = -2x/3
-2x = 3(y + 8)
x = (-3/2)(y + 8)
x(y) = -(3/2)y - 12
Method 2:
Make the parameter t the subject of the y component equation,
y = -8 + 2t
y + 8 = 2t
t = (y + 8)/2
Then, substitute in the x(t) equation:
x = -3[(y + 8)/2]
x(y) = -(3/2)y - 12