If tanA=3/5 find the value of xsinA+ycosA. Please help!!

Answer 1

Draw and label a diagram!

If tan A = 3 / 5, then sin A = 3√34 / 34 and cos A = 5√34 / 34 .

Assuming x = 5 and y = 3 (The problem is deficient in this regard)

5(3√34 / 34) + 3(5√34 / 34)

30√34 / 34

15√34 / 17

Answer 2

Start by drawing a picture....

A right triangle has one side that is the longest---this is the hypotenuse and its length is the square root of the sum of the squares of the other 2 side.

Suppose the two sides are actually 3 and 5. The hypotenuse is then √34. the opposite side of the angle is 3 and the adjacent is 5.

The sin of the angle is then 3 / √34 and the cosine is 5 / √34