
Chlo A.
asked 03/01/20need help with polar question
A curve with a polar equation, r=28/6sinθ+25cosθ represents a line. This line has a Cartesian equation of the form y=mx+b,
where m and b are constants. Give the formula for y in terms of x. For example, if the line had a equation
y=2x=3 then the answer would be 2⋅x+3.
Y= ?
3 Answers By Expert Tutors

William W. answered 03/01/20
Experienced Tutor and Retired Engineer
Assuming this problem is r = 28/(6sin(θ) + 25cos(θ)) then multiply both sides by "6sin(θ) + 25cos(θ)" to get:
r(6sin(θ) + 25cos(θ)) = 28 then distribute the "r" to get:
6rsin(θ) + 25rcos(θ) = 28
Now we use the conversion between polar coordinates to Cartesian coordinates which are:
x = rcos(θ)
y = rsin(θ)
Substituting "x" for "rcos(θ)" and "y" for "rsin(θ)" we get:
6y + 25x = 28
6y = -25x + 28
y = -25/6x + 28/6
y = -25/6x + 14/3
You can use Desmos to graph both equations (one in polar, and the other in Cartesian coordinates) and then look to see they are the same.

Mark M. answered 03/01/20
Mathematics Teacher - NCLB Highly Qualified
r (6 sin θ + 25 cos θ) = 28
r (6x / r + 25y / r) = 28
6x + 25y = 28
25y = -6x + 28
y = -6x/25 + 28/25
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Mark M.
The entire denominator should be in parentheses!03/01/20