Raymond B. answered 03/05/20
Math, microeconomics or criminal justice
81 < x + (x+1) + (x+2) <99
81 < 3x+3 < 99
divide by 3
27 < x+1 < 33
subtract 1
26 < x < 32
x is in the interval [27,31]
x is either 27, 28, 29, 30 or 31
x plus the next two integers = 27+28+29 = 84
or = 28+29+30 = 87
or = 29+30+31 = 90
or = 30+31+32 = 93
or = 31+32+33 = 96