
Chlo A.
asked 02/21/20trig need help, with one last equation in my problem
If sinx=49, x in quadrant I, then find (without finding x)
sin(2x)= 2(4/9)(sqrt(65)/9)
cos(2x)= 1-2(4/9)^2
tan(2x) = ?
3 Answers By Expert Tutors

Edward A. answered 02/23/20
High School Math Whiz Grown Up--I've even tutored my grandchildren
Chlo, it’s always easier for the tutors to work your problem if it is accurately written. When you wrote “sin(x) = 49”, it is confusing, because the value of sin is never more than 1. The value 49 is clearly a mistake. From the other lines of the problem, we can guess that it was actually supposed to be
“4 / 9”

Sam Z. answered 02/22/20
Math/Science Tutor
sin/cos=tan so; 2(4/9)(sqrt(65)/9)/1-2(4/9)^2
8/9*(8.062...../9)/(1-2(16/81))
.888*.895 / 1-32/81
796.27 / .605
1.3162.....
atan=52.775.......°
Hi Chlo. Assuming your answers for sin(2x) and cos(2x) are correct (which I think they are), then by definition tan(2x) = sin(2x)/cos(2x). Remember to rationalize the denominator if necessary.
Robert

Robert C.
02/21/20
Still looking for help? Get the right answer, fast.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Mark H.
The sine of an angle cannot be greater than 1, so something has been copied incorrectly. (It looks like you might have meant sinx = 4/9.....) The last three lines are all what you are supposed to calculated based on line 1??02/21/20