Inactive Tutor answered 02/14/20
500/.022=22.727..........yrs
Here's a formula: fv=p(1+.022/2)^(nt)
20,222(1.022)^1=20,440
n=yrs 2=20,889
1.5=20,63
1.25=20,551
1.125=20,495
1.126=20,496
1.135=20,500
future value
premium
int
compound
years
times/yr
Eva M.
asked 02/13/20Terry is given two salary options by his employer. The first option is a starting salary of $20,000 that
increases by $500 each year he is with the company.
The second option is a starting salary of $20,000 that increases by 2.2% each year he is with the company.
How many years will Terry have to be with the company for the salary with the second option to be
greater than the salary with the first option? SHOW ALL WORK!
A.11 B.12 C. 13 D. 14
Inactive Tutor answered 02/14/20
500/.022=22.727..........yrs
Here's a formula: fv=p(1+.022/2)^(nt)
20,222(1.022)^1=20,440
n=yrs 2=20,889
1.5=20,63
1.25=20,551
1.125=20,495
1.126=20,496
1.135=20,500
future value
premium
int
compound
years
times/yr
Inactive Tutor answered 02/14/20
If you have a TI graphing calculator, you could graph the two option and find when the exponential is higher than the line.
The equations would be y1=20,000 + 500x and y2=20,000 + 2.2x
Or you could plug in 11,12,13 and 14 in for x for each equation until the y2 gave you a larger value.
Eva M.
but what's the answer? a,b,c,d02/14/20
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Eva M.
this isn't an investment, this is an exponential problem...02/14/20