
William W. answered 02/16/20
Experienced Tutor and Retired Engineer
Part A: I would pick a cosine wave since the function starts first at the max (July 4 is the highest low tide) and cosine starts at the max. But it really isn’t critical, just requires a different phase shift.
Part B: The amplitude is the max - average so 1.8 - 0.2 or 1.6 feet. The meaning is how far the tide varies from the average.
Part C: The vertical shift is the average - zero so 0.2 - 0 or 0.2 feet. The meaning is that the average low tide is 0.2 feet above sea level.
Part D: The phase shift is 4 days. That’s the time delay of this wave from the standard cosine wave. If we did not apply a phase shift the maximum would occur at time t = 0 or the first day. No times are given so we assume the time of day is unimportant in this context (which, by the way, is probably untrue)
Part E: The function h(t) where “h” represents the height of the low tide and “t” represents the time in days beginning July 1 is: h(t) = 1.6cos(pi/7(t - 4)) + 0.2
Part F: Sketching out the curve, we see that the cosine wave crosses the “average” 3.5 days prior to its max on July 4 and then it would be “average” on day 0.5, day 7.5, day 14.5, day 21.5, and day 28.5 for a total of 5 times. Decimal aliens would just represent portions of a day.
Part G: Variations could occur due to other gravitational factors (alignment or misalignment of the sun & moon or other planets) or local geographic features (bays, inlets, etc).
Rimi S.
How did you get pi/7 for the period?03/19/20

William W.
The period is not pi/7. It is 14 days. Remember that the number in the equation (typically referred to as "B") is not the period but 2pi/period. So since the period is 14 days (twice the time between the highest low tide and the lowest low tide), then B = 2pi/14 = pi/7.03/19/20
David P.
Thank you so much for the help.02/18/20