Yefim S. answered 02/07/20
Math Tutor with Experience
Let T = Asin(Bt + C) + D,
where T is temperatura in F, t is time in hours.
Then D = (75 + 85)/2 = 80°F, A = (85 - 75°)/2 = 5°F.
We have now equation: T = 5sin(At + C) + 80.
Letcoount timeromfmidnite. Then if t = 9 then T = 80°F. We get equation: 8i0 = 5sin(9B + C) + 80,
5sin(9B + C) = 0, sin (9B + C ) = 0, 9B + C = 0, C = - 9B.
Fro the other side B = 2π/24 = π/12, because period p = 24 hours. From here C = -9π/12 = -3π/4.
We get finaly equation: T = 5sin(π/12·t - 3π/4) + 80.
Now we have to find first time when T = 79°F.
We get trigonometric equation: 5sin(π/12·t - 3π/4) + 80 = 79, from here sin(π/12·t - 3π/4) = -0.2;
From here π/12·t - 3π/4 =sin-1(0.2), t =(3π/4- sin-10.2)/(π/12) = 8.23 hours
At t = 8.23 hoursr AM temperature first time will be 79°F