please help with chem!

Question

Antimony has two naturally occuring isotopes, ${}^{121}{Sb}$ and ${}^{123}{Sb}$ . ${}^{121}{Sb}$ has an atomic mass of $120.9038 u$ , and ${}^{123}{Sb}$ has an atomic mass of $122.9042 u$ . Antimony has an average atomic mass of $121.7601 u$ . What is the percent natural abundance of each isotope?

121Sb:

123Sb:

Arturo O. · Accepted Answer

Find the weighted average:x = percentage of 121Sb100 - x = percentage of 123Sbx(120.9038) + (100 - x)(122.9042) = 100(121.7601)Solve for x and finish from here.

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please help with chem!

1 Expert Answer

Still looking for help? Get the right answer, fast.

OR

RELATED TOPICS

RELATED QUESTIONS

what are all the common multiples of 12 and 15

need to know how to do this problem

what are methods used to measure ingredients and their units of measure

how do you multiply money

spimlify 4x-(2-3x)-5

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