How do I solve this algebraic properties of exponents problem?

Question

8x^0z^2)

/(2y^8) -1 Its basically a full parenthese exponent problem and on the side(right) is -1 not by any invidual numbers but by 1?

Its properties of exponents and I have no idea how to solve it

(8xˆ0zˆ2)/(2yˆ8)-1

or

\left(\frac{8x^0z^2}{2y^{^8}}\right)-1

Answer 1

Hi Eva,

I don't see a an equal sign or an inequality sign.

"Solving" requires a sign of relationship.

Expressions can be simplified, but if that is the task, the given problem seems to be lacking in the instructions.

Please clarify if possible.

aa

Answer 2

Hi Eva M.,

I'm not sure the problem you present is correct, but here it is as it appears.

[( 8x^{0z^2} ) / (2y⁸ )] -1 = , (x^{0z^2} = 1)

[ 8 / (2y⁸ )] - 1 =

[ 8 / (2y⁸ )] - ( 2y⁸ ) / ( 2y⁸ ) =

( 8 - 2y⁸ ) / ( 2y⁸ ) =

( 4 - y⁸ ) / y⁸

Let me know, Joe.

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Edit: Is this correct?

a.) [( 8x⁰z² ) / (2y⁸)] - 1,

Or this:

b.) (8x⁰z²) /(2y⁸ - 1)

We'll get it set up right eventually Eva M.