Arthur D. answered 12/18/19
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
distance=rate*time
d=r*t
Joe: 20=r*4
r=20/4
r=5 mph
Mary's rate is 5-2=3 mph
Mary: d=r*t
20=3*t
20/3=t
t=6 2/3 hours for Mary to travel down the river
Will J.
asked 12/18/19Joe and Mary left a campsite on a trip down the river in a canoe. Joe was traveling 2 miles/hr faster than Mary. If it took Joe 4 hours to travel 20 miles, how long will it take Mary?
How do I solve this? I am very confused.
Arthur D. answered 12/18/19
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
distance=rate*time
d=r*t
Joe: 20=r*4
r=20/4
r=5 mph
Mary's rate is 5-2=3 mph
Mary: d=r*t
20=3*t
20/3=t
t=6 2/3 hours for Mary to travel down the river
Bryce P. answered 12/18/19
CRLA Certified Mechanical Engineering Tutor w/ 1,500 hrs of experience
Hi Will,
This question is based on uniform velocity which is equal to the change in position divided by the change in time. In equation form:
v = Δx/Δt.
In your case, I'm going to use vJ for Joe's velocity, and vM for Mary's velocity. We are told that Joe is going 2 miles/hr faster than Mary. This means that:
vJ = vM + 2
We are also told that Joe traveled 20 miles in 4 hours. This is his velocity!
vJ = 20 miles/4 hrs = 5 miles/hr
If we know vJ we can use plug this into our equation above to solve Mary's velocity.
vJ = vM + 2
5 = vM + 2
vm = 3 miles/hr
I hope that helps! If you are still confused let me know.
Bryce
Sam Z. answered 12/18/19
Math/Science Tutor
m+2=j
(m+2)4=20
4m+8=20
4m=12
m=3
speed*time=distance
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