In a normal distribution with mean of 900 and standard deviation is 350 find the probability that a data value picked at random is greater than 1100

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Answer 1

P(X>1100) = ?

Z-score of 1100 = (1100 - 900) / 350 = 4/7 = 0.571

Using the z table we get the area P(X>1100) = 0.284

And the area will be subtracted from 1 to find P(X>1100) = 1- 0.284 = 0.716