Algebra integers

Question

The greater of the two consecutive integers is 10 less than twice the smaller. Find the integers.

Answer 1

two consecutive numbers: x, x+1

2x-10 = x+1

x = 11

numbers: 11, 12

Answer 2

Let "n" be the smaller integer. That means the larger integer is "n + 1"

The greater ("n + 1") is ten less than twice the smaller. Well, "twice the smaller" would be "2n" and 10 less than that would be 2n - 10 so:

n + 1 = 2n - 10 (subtract n from both sides:

1 = n - 10 (add 10 to both sides:

11 = n

So the smaller integer is 11 and the larger integer is 12

Answer 3

Let "n" be the smaller integer. That means the larger integer is "n + 1"

The greater ("n + 1") is ten less than twice the smaller. Well, "twice the smaller" would be "2n" and 10 less than that would be 2n - 10 so:

n + 1 = 2n - 10 (subtract n from both sides:

1 = n - 10 (add 10 to both sides:

11 = n

So the smaller integer is 11 and the larger integer is 12