Bob M.

asked • 12/08/19

Physics, work problem

A mover is pushing a 20-kg box up a 30-degree ramp from the ground into a moving truck. He pushes with a constant velocity up the 2.1m ramp. He pushes it without rollers where the coefficient of kinetic friction is 0.3.


a) what is the force of friction?

b) what is the pushing force applied by the mover?

c) what is the work done by the mover?

d) what is the work done by the force of gravity?

e) what is the work done by the normal force?

f) what is the work done by the force of friction?

1 Expert Answer

By:

Mark H. answered • 12/08/19

Tutoring in Math and Science at all levels

Bob M.

Could Fnet,x be represented as: Fa-Fgx-Ff,k? Thus, Fa=ukFn+fgx which is Fa=(0.3*200)+200sin30=160N
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12/09/19

Bob M.

160 being the pushing force applied by the mover and 60 (0.3*200) being the force of friction
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12/09/19

Mark H.

tutor
Please see the addendum added above.
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12/10/19

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