The area of the rectangle is 50 yd2. What is the length of side y?

Answer 1

Since the area of a rectangle is Length * Width, we can represent this as Area = X * Y. Then, if area = 50, we can write this as: X * Y = 50. Dividing both sides by X gives the final answer of Y = 50 / X.

Answer 2

The area of the rectangle is 50 yd2. What is the length of side y?

First I want to assume that the following is the right question:

The area of the rectangle is 50 yd². What is the length of side y?

RECTANGLE

Rectangle. A 4-sided flat shape with straight sides where all interior angles are right angles (90°). Also opposite sides are parallel and of equal length. Example: A square is a special type of rectangle.

Rectangle

The formula is: A = L * W where A is the area, L is the length, W is the width, and * means multiply.

The area of a rectangle is the length times the width because you are calculating the square units of a rectangle. A square unit is simply a 1 x 1 units. Therefore, multiplying the total number of unit squares in the length of a rectangles by the total number of squares in the width of the rectangle give you the total number of squares 1 x 1 on the rectangle.

EXAMPLE?

YES

Consider a rectangle of length 5 units and width 3 units. We can divide this rectangle into unit squares:

Each of those squares are 1x1=1

If we gave value to length and width ( in case we said that length = 5 and width = 3 ) and we have or you have been introduced to geometry and look up the formula for finding the area ( which was Area = Length x Width or A=LxW ( using Symbols ) then the

AREA OF TOP EXAMPLE OF RECTANGLE

A = L x W

A= 3 x 5

15 = 3 x 5

Area would be 15 unit squares ( flat view from top each 1x1 = 1 discussed earlier totaled 15 ).

YOUR QUESTION?

The area of the rectangle is 50 yd². What is the length of side y?

Area of rectangle is length times width:

A=L(W)

50=L(W)

 

The width is 1/2 the length:

W=L/2

 

Substitute. Replace the W in the first equation with L/2:

50=L(W)

50=L(L/2)

50=L²/2

100=L²

10=L

 

Plug in 10 for L in either equation to solve for W:

W=L/2

W=10/2

W=5

 

The length is 10yd, and the width is 5yd

IF WE SUBSTITUTE

LET A = AREA

LET L = Y OR LENGTH

LET W = WIDTH

LET US SOLVE

A=LxW

A=YxW

SOLVE FOR Y

50Yd² / W = Y

50Yd² / 10Yd = 5 Yd

Y = 5 Yd

Y equals 5 yards if width equals 10 yards and 5 yd x 10 yd equals 50 yd²

LOOK UP ROWS AND COLUMNS

UNITS

TAKEA SECOND LOOK AT RECTANGLE ABOVE

DRAW ANOTHER RECTANGLE

EACH UNIT IS 1 ( LITTLE SQUARES )

DRAW 5 ROWS

DRAW 10 SQUARES ON EACH ROW

YOU WILL SEE THAT YOU HAVE 50 UNIT SQUARES

UNTIL THEN

P.S.

The area of a rectangle (A) is related to the length (L) and width (W) of its sides by the following relationship: A = L ⋅ W. If you know the width, it's easy to find the length by rearranging this equation to get L = A ÷ W. If you know the length and want the width, rearrange to get W = A ÷ L. formula that can help?

You can also give values to parts of rectangle.

Y = A/W

The answer can be several depending on value of unknowns.

Variables are unknowns

Y substituted for L ( Length ) can be

1,2,5,10,50

Remember

Most tests are multiple choice

Use the statement, reason, given, definitions, substitutions, algebra, and look at formulas.

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