Greg F. answered 12/02/19
Math Expert|Masters in Electrical Engineering|8 Years Experience
Professor Robertson has at least one girl, so that means there are only 3 possible situations for Professor Robertson, Child A is a girl and Child B is a boy, Child A is a boy and Child B is a girl, or both children are girls. There is only one way that Professor Robertson can have two girls, so the probability that she has two girls is 1/3.
We already know that Professor Simpson has 1 girl, so then there are only two possible situations for Professor Simpson, the older child is a girl and the younger child is a boy, or both children are girls. There is only one way Professor Simpson can have two girls, so the probability that she has two girls is 1/2.