Let M = money at the end of the period
I = the annual interest rate
Mo = money invested at the beginning of the period
n = the number of periods
t = time in years
1) M = Mo(1 + I/n)nt $350,000 = Mo(1 + .0425/12)(12*4) = Mo(1.18495)
or Mo = $295,371.40
2) You know that the money invested quarterly will always earn more that the simple interest by general rule!
In the first case, M = 100,000(1 + .05)4 = 121,550.63 So, the interest earned is $21,550.63
In the second case, M = 100,000(1 + .05/4)(4*4) = 121,988.95 So, interest earned is $21,988.95
Therefore, she earns $21,988.95 - $21,550.63 = $438.32 more with quarterly compounding!