PLEASE ANSWER ASAP THANK YOU!!

Question

If a rifleman averages 8 hits out of 10 shots at a target, what is the probability that he will hit the target in 3 out of 4 shots?

show work please

Answer 1

So, the probability of hitting the target is 8/10 or .8

Then the probability of hitting exactly 3 out of 4 shots would be

₄C₃(p)³(q)^(4-3) where C is the combination symbol, p is the probability of success & q is probability of failure

So, 4!/(4-3)!3! = 4 and 4(.8)³(.2)¹ = .4096 probability of hitting 3 out of 4 shots!