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Jen S.

asked • 11/18/19

What volume (in mL) of 4.46 M HCl is required to fully react with 19.3 mL of 2.13 M Ca(OH)2?

Consider the following balanced equation.

2HCl (aq) + Ca(OH)2 (aq) LaTeX: \longrightarrow 2H2O (l) + CaCl2 (aq)

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