Liz Z. answered 01/02/20
Middle school - College math tutor. I love math, and you can too!
Yes! There is absolutely a quick way to calculate this! (I assume you mean multiples, not factors, as the only factors of three are one and three, so there are none between 100 and 200.) All numbers that are multiples of three have digits that sum to multiples of three, so I know 102 is the smallest multiple of three in this range, since 1+0+2=3, and 3 is divisible by 3. 198 is the largest, since 1+9+8=18, and 18 is divisible by 3.
Knowing the first and last values, I used the arithmetic sum formula with a common difference, d=3 and first term=102:
an=3(n-1)+102.
Using 198 as an, the "current" or nth term, I solved for n to find the number of terms:
198=3(n-1)+102. Subtract 102 from both sides to get
96=3(n-1). Divide by 3 to get
32=n-1. Add one to get
33=n
So 198 is the 33rd term in this sequence of numbers, which are all the multiples of 3 between 100 and 200. That's how many multiples of three there are.
Also, if you're not familiar with arithmetic sequences, check out this intro in Purple Math: https://www.purplemath.com/modules/series3.htm
or, for something more comprehensive, search for "arithmetic sequences" on www.khanacademy.org.
Happy mathing!
Liz Z.