
Mark M. answered 11/15/19
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
yx3 = k
(15)(11)3 = k
19965 = k
y(17)3 = 19965
4913y = 19965
y = 4.063708528
Alanna M.
asked 11/15/19Mark M. answered 11/15/19
Mathematics Teacher - NCLB Highly Qualified
yx3 = k
(15)(11)3 = k
19965 = k
y(17)3 = 19965
4913y = 19965
y = 4.063708528
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