Arman G. answered • 11/11/19

Aerospace Engineer

- F
_{net }= m*a = 2000 - 600 = 500*a, solve for a - F
_{net }= 22 + 14 + 30 -72 = -6N or just 6N to the left so 6 = m*a so acceleration is 6/5 or 1.2 m/s^{2}to the left - F*d = Change in kinetic energy, we want it to stop so change is the current kinetic energy (like if you have 5 joules of energy and need to stop thats a change of 5 joules to get to zero joules) so

So F*1 = 0.5*1600*(14^{2}) so solve for F