J.R. S. answered 10/23/19
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
Let the unknown base be B
In aqueous solution, you have...
B + H2O ==>BH+ + OH-
From the pH of 8.39, we can now find the [OH-] which will also be [BH+]:
pH = 8.39
pOH = 14 - 8.39 = 5.61
[OH-] = 1x105.61 = 2.45x10-6 M = [ BH+]
And we know that Kb = [BH+][OH-]/[B], so we can now solve for Kb:
Kb = (2.45x10-6)(2.45x10-6)/0.24
Kb = 2.5x10-11
pKb = -log Kb
pKb = -log 2.5x10-11 = 10.6