what are two consecutive integers who’s sum is 465.

Answer 1

Let x be one number. A consecutive number will be 1 more than x. So the other number is x + 1

x + x + 1 = 465

2x + 1 = 465

2x = 465 -1

2x = 464

x = 464/2 = 233.

Since x = 233, x + 1 = 234.

The two consecutive numbers are 233 and 234.

Answer 2

if the small one is x, the other one is (x + 1)

then

x + (x + 1) = 465

2x + 1 = 465

2x = 464

x = 232

Answer 3

Let x = the smaller integer. Then x+1 must be the larger integer, since the integers are consecutive.

Therefore, 465 = x + (x+1) = 2x+1

Subtract 1 from both sides to get

464 = 2x

Divide both sides by 2 to get

232 = x. Therefore, the two consecutive integers are 232 and 233