Trey and Catherine are traveling towards each other from points that are 495 miles apart. If Catherine is traveling 11 mph faster than and they meet after 9 hours, how fast was each traveling?

Answer 1

495=(C+T)(9) distance = total speed times time of 9 hours

C=T+11

495=(T+11+T)(9)

495=(2T+11)(9)

495=18T+99

18T=396

T=22 mph

C=33 mph

495=(22+33)(9)=55(9)=495 miles