Twice the difference of a number and 2 is more than 5 less than three times the number.

Answer 1

Twice the difference of a number and 2 is more than 5 less than three times the number.

=>

let number = n

difference of a number and 2 = n-2

Twice the difference of a number and 2= 2(n-2)

three times the number= 3n

5 less than three times the number= 3n-5

2(n-2) > 3n-5

2n-4 > 3n-5

add 4 to both sides

2n > 3n-5+4

2n > 3n-1

subtract 2n from both sides

-n > -1

multiply with -1 to both sides

n < 1

Answer 2

Turn the words into an equation

... Twice the difference of a number and 2 ... 2*(N-2)

... Five less than 3 times the number ... 3*N-5

... is more than >

results in 2*(N-2)>3*N-5 ... solve this equation

... expand 2*N-4>3*N-5

... get all the "N's" on one side by subtracting 2*N from both sides ... -4>N-5

... get N alone by adding 5 to both sides ... 1>N

the answer is that N must be less than one