MATH HELP TRIGONOMETRY

Question

TV screens are measured on the diagonal. If we have a TV-cabinet that is 62 inches long and 50 inches high, how large a TV could we put in the space (leave 2-inches on all sides for the edging of the TV)? Round your answer to the nearest tenth.

Answer 1

Well then it will fit a TV that is 60 by 48

sqrt( 60^2 + 48^2) = sqrt( 3600 + 2304) =

sqrt(5904) =

sqrt(16 * 369) =

sqrt(16 * 9 * 41) =

sqrt(16)*sqrt(9) * sqrt(41)

4 * 3 * sqrt(41) =

12*Sqrt(41) = 76.8 to the nearest tenth per the directions

Answer 2

The available area is 58 x 46 (draw and label a diagram!)

The diagonal of the the largest TV that can fit is

d² = 58² + 46⁶