Jason has one and half times as many books as Ramon. Together,they have 45books .How many books does each by have ?

Answer 1

If we let x represen . . . . eh, scratch that; everyone uses x so let's use b (you know, for books). If we let b stand for how have books Ramon has, then the if Jason has 1 1/2 times as much, he would 1.5×b,or just 1.5b. Together means you add them up (so 1.5b + b) and you get 45 -----> So 1.5b + b = 45.

Now just add the like terms (remember that b = 1b if that helps) and then solve the equation by dividing and that should give you the answer. Well, to be precise, that will give tell you what b is, which is how many books Ramon has. You will then have to multiply that number by 1.5 to get how many Jason has.

I hope this helps. Have a great day!

Answer 2

We can solve this by turning each person's number of books into an equation.

If Jason has 1 and a half times as many books as Ramon, we can say Jason has 1.5*R books

In this situation, R is the number of books Ramon has.

Ramon and Jason together have 45 books, so we can assume R + 1.5*R = 45. Remember, Jason has 1.5*R books

From here take 1.5*R + R to make 2.5*R = 45

To solve for R, divide both sides by 2.5

Thus R = 18, so Ramon has 18 books

Jason has 1.5*R or 1.5*18 = 27 books

To double-check the work, add 18+27 = 45 to know that their sum of books is indeed 45

Answer 3

Let's say Jason's book = j, Ramon's books =r

Jason has one and a half times as many as Ramon, so j = 1.5 * r

together they have 45, so j + r = 45

we can use substitution to find that 1.5r +r = 45

so 2.5r = 45, and lastly r = 18

now we know j +18 = 45, and so 27.

we can check our work, and since 18 * 1.5 =27, this answer seems correct