I think what this problem means is this:
w=speed of the current
upstream (against the current) distance: (w-12)*60
downstream (with the current) distance: (w+12)*36
60(w-12)=36(w+12)
divide by 6
10w-120=6w+72
4w=192
w=12 (mph)
Mary A.
asked 08/13/19A motorboat can maintain a constant speed of | 12 miles | per hour relative to the water. The boat makes a trip upstream to a certain point in | 60 minutes | the return trip takes | 36 minutes | What is the speed of the current? |
I think what this problem means is this:
w=speed of the current
upstream (against the current) distance: (w-12)*60
downstream (with the current) distance: (w+12)*36
60(w-12)=36(w+12)
divide by 6
10w-120=6w+72
4w=192
w=12 (mph)
The distance up steam and down stream are equal. The current speed is equal in both directions but opposite. The up steam rate is 12 miles/hours - Current miles/ hour and the down steam is 12 miles/hour + Current miles/hour. The times must be converted into hours since the speeds are in hours. 60 minutes = 1 hour and 36 minutes = 36 /60 or 0.6 hours. The equality becomes: 1 (12- C) = 0.6 ( 12 + C).
Multiplying through: 12 - C = 7.2 + C
Add C to both sides: 12 = 7.2 + 2 C
Subtract 7.2 from both sides: 4.8 = 2 C
Divide by 2: 2.4 miles/ hour = C
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