Joy J. answered 08/06/19
College Level Calculus Instructor - - 1/2/3 and applied
Since the first one reduces to the sum of [(-1)^n]/[4 n^(1/7)] this is divergent by comparison with p-series. (If a series fails to converge by the alternating series test and its absolute series diverges, then the series is divergent, if I'm not mistaken - - this series fails the test for convergence by alternating series and its corresponding absolute value series fails by p-series comparison.)

Joy J.
08/06/19
John S.
Your reduction is correct, but it does converge by the alternating series as for alternating series our only requirement is that the non-alternating component of the series approaches 0 in the limit as n approaches infinity and that it is always decreasing. Alternating series can converge even when the corresponding p-series would not, with the classic example being that the harmonic series does not converge but the alternating harmonic series does.08/06/19