Avas A.

asked • 08/06/19

Convergent or Divergent?

Match each of the following with the correct statement.

A. The series is absolutely convergent.

C. The series converges, but is not absolutely convergent.

D. The series diverges.


a) sigma (n=1 to inf) [(-1)^n 2^(n-1)]/[2^(n+1) n^(1/7)


b) sigma (n=1 to inf) n^4/7^n


c) sigma (n=1 to inf) (n+2)!/[(3^n)(n!)]


d) sigma (n=1 to inf) (-1)^n (n!)/ 5^n


e) sigma (n=1 to inf) (-1)^n / [6^n n!)


Thank you!

1 Expert Answer

By:

John S.

Your reduction is correct, but it does converge by the alternating series as for alternating series our only requirement is that the non-alternating component of the series approaches 0 in the limit as n approaches infinity and that it is always decreasing. Alternating series can converge even when the corresponding p-series would not, with the classic example being that the harmonic series does not converge but the alternating harmonic series does.
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08/06/19

Joy J.

tutor
yes, I agree, now that I think about it, of course the seventh root is everywhere increasing (the other requirement for alternating series convergence) - - so conditionally convergent! :)
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08/06/19

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