, what is the ground distance, to the nearest foot, from the point directly below the airplanes location to the runway

Question

An airplane is at a cruising height of 9,850 feet. If the angle of depression to the runway is 15°, what is the ground distance, to the nearest foot, from the point directly below the airplanes location to the runway

Answer 1

a=9850

γ=90º

α=15°

β=75°

a/(sinα)=b/(sinβ)=c

9850/.259=b/.966+c

c=38057.4 *.966=36763.52=b