- For an equals absolute value problem, you simply have two (possible) answers. Set up the problem for the negative possibility and the positive one:
- 4a-2=10 OR 4a-2=-10
- 4a=12 OR 4a=-8
- a=3 OR a=-2
- For a less than situation, you will have a (possible) range, that is of the form a<x<b. Start by setting up your absolute value piece as between the negative and positive number you start with.
- -12 < 9-3g < 12
- -21 < -3g < 3
- 7 > g > -1 (remember multiplying or dividing by a negative number turns things around)
- -1 < g < 7 (putting it back into the right order)
- For a greater than situation, you will have two "tails" so to speak of allowable values. Start by setting up two distinct problems using the positive and negative starting value
- x-5<-3 OR x-5>3
- x<2 OR x>8
Sierra D.
asked 01/14/15what is |4a-2|=10 etc.?
Solve each equation or inequality
1)|4a-2|=10
2)|9-3g|<=12
3)|x-5|> 3
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