NEED HELP IMMEDIATELY!!!!

Question

1.Write an expression to represent any angle coterminal with the angle 320° (n is an integer).

A)320∘+n(180∘) B)320∘−n(180∘)

C) 360∘+n(320∘)

D) 320∘+n(360∘)

2.Given that 0∘≤C≤180∘, determine the value(s) of ∠C to the nearest degree when sinC=0.9848.

A) 80°, 100°

B) 100°

C)10°, 80°

D)80°

3.Consider angles A, B, and C such that cosA=cos317∘, tanB=tan198∘, sinC=sin17∘, where 0∘≤A≤360∘, 0∘≤B≤360∘, 0∘≤C≤360∘. Suppose that A≠317∘, B≠198∘, and C≠17∘. The value of A+B+C is

A)532 Degrees

B) 78 Degrees

C)224 Degrees

D)498 Degrees

4.θ is an angle in standard position whose terminal arm is in quadrant IV and cosθ=313−−√. Find cscθ.

Answer 1

1) D any circle plus 320

2) inverse_sine( 0.9848 ) is about 80 degrees.

sine is positive in quadrants 1 and 2.

So 80 and 180-80 = 100

So A

3) cosine is positive in quadrants 1 and 4

360 - 317 = 43, so cos 43 = cos 317 = 0.731353

tangent is positive in quadrants 1 and 3.

198 - 180 = 18, so tan 198 = tan 18 = 0.32491969623....

sine is positive in quadrants 1 and 2.

180 -17 = 163, so sin 17 = sin 163 = 0.2923...

43+18+163 = 224 so c

4) 360 -313 = 47 , so cos 313 = cos 47 since cosine is positive in quadrants 1 and 4

the sin is negative in quadrant 4, and then so is the cosecant.

the answer is -1.3673274610985952952732138680262