
Elizabeth P. answered 07/17/19
Patient math/stats tutor with Ph.D. in Psychology
First question, solve for L in terms of R.
S = πr2 + πrL
We know S = 1100, so
1100 = πr2 + πrL
We want to get L by itself. Subtract πr2
1100 - πr2 = πrL
Now divide by πr.
(1100 - πr2) / (πr) = L
Second question, write Volume in terms of r only
V = 12 π r2 L
Replace "L" with what we solved for above: (1100 - πr2) / (πr)
V = 12 π r2 (1100 - πr2) / (πr)
Not sure if they want you to simplify that or if the above equation will suffice.
Third, find the value of r that maximizes the volume of the hut. The above equation is a quadratic, as it has both an r2 and r term. So the maximum volume is going to be the vertex of the parabola.
If you can use a graphing calculator, graph the V equation above and use trace to find the vertex. The x-value of the vertex refers to the radius (the y-value is the volume)
If your teacher is mean, then you'll have to simplify the equation and get it into ax2 + bx + c = 0 form and solve using the quadratic equation. That will get messy!