
Patrick B. answered 07/11/19
Math and computer tutor/teacher
6a + 4b + 5c = 47
4a + 2b + 2c = 26
2a + 6b + 8c = 44
divides 2nd and 3rd equations by 2:
6a + 4b + 5c = 47
2a + b + c = 13
a + 3b + 4c = 22
Eliminates A:
Pairs equations #1 and #2:
6a + 4b + 5c = 47
2a + b + c = 13
-3 * Equation #2 + Equation #1:
b + 2c = 8
Pairs equations #2 and #3:
2a + b + c = 13
a + 3b + 4c = 22
-2 * equation #3 + equation #2:
-5b + -7c = -31
5b + 7c = 31 <--- multiplies everything by -1
2 by 2 system from equations above in bold:
b + 2c = 8
5b + 7c = 31
solves by substitution: b = 8 - 2c
5(8 - 2c) + 7c = 31
40 - 10c + 7c = 31
40 - 3c = 31
-3c = -9
c = 3
Then b = 8 - 2(3) = 8 - 6 = 2
Simplified second equation: 2a + b + c = 13
2a + 2 + 3 = 13
2a = 8
a = 4
Check:
6(4) + 2*4 + 3*5 = 24 + 8 + 15 = 47
4*4 + 2*2+ 2*3 = 16 + 4 + 6 = 26
4*2 + 6*2 + 3*8 = 8 + 12+ 24 = 44
A=4 B=2 C=3
Amanda B.
thank you so much you’re the best07/11/19