Syd T.

asked • 07/10/19# Conservation of Energy

If a roller coaster begins at rest at the top of a 26 meter hill, then at the bottom of the hill how fast will it be going?

## 1 Expert Answer

Eugene E. answered • 07/11/19

University Physics, Electrodynamics, and Quantum Mechanics Tutor

Let m and v be the mass and speed, respectively, of the coaster. By conservation of energy, the gain in kinetic energy as the coaster reaches the bottom is equal to the potential energy lost: mv^{2}/2 = 26mg. Dividing the equation by m and multiplying by 2, v^{2} = 52g. Taking the square root on both sides, v = √(52g) = 23 m/s.

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William W.

I did your Conservation of Energy 5 problem. This one is just like that so take a look and follow the same process07/10/19