Let S = sales and P = price R=revenue
(288-268)/(30-35)=(S=288)/(P-30) => S=408-4P
R = S*P = =408P-4P2
dR/dP = 408 - 8P and the maximum will be at P=51.
William G.
asked 07/05/19When a wholesaler sold a product at $30 per unit, sales were 288 units per week. After a price increase of $5, however, the average number of units sold dropped to 268 per week. Assuming that the demand function is linear, what price per unit will yield a maximum total revenue?
Let S = sales and P = price R=revenue
(288-268)/(30-35)=(S=288)/(P-30) => S=408-4P
R = S*P = =408P-4P2
dR/dP = 408 - 8P and the maximum will be at P=51.
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