Linda C. answered 01/11/15
Tutor
5
(1)
Engaging teacher fro Calculus, Precalculus, Trigonometry, and Algebra
Think carefully about the wording of this problem. The function itself defines height, or how high the projectile goes. You are asked about the maximum horizontal distance. This is still a vertex problem, but once you find your x value, you want to double it, to get the up and down complete path.
The x value of the vertex is just -b/(2a), where a and b are coefficients. For this parabola, a=-1 and b=2, so your vertex occurs at -2/-2=1. The maximum horizontal distance is thus 2 meters.