Consuela A.
asked 01/11/15average percentages
Assume that there were 18 working days in February and that the six clerks in your unit had the following number of absences:
CLERK F - 3 absences
CLERK G - 2 absences
CLERK H - 8 absences
CLERK I - 1 absence
CLERK J - 0 absences
CLERK K - 5 absences
The average percentage attendance for the six clerks in you runit in February was most nearly_________%
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1 Expert Answer
Logan D. answered 01/11/15
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Expert Teacher: Calculus, Differential Equations & Physics for Success
Since there are six clerks and each could have worked 18 days, then the total # of possible days worked would be 6 x 18 = 108 days.
Looking at the data, we can see that the total number of absences is 3 + 2 + 8 +1 + 0 + 5 = 19. Thus, the total # of days worked = 108 days - 19 = 89 days.
Since there are six clerks, then the average # of days worked for each clerk is: 89 day / 6 clerks ≈ 14.833 days per clerk.
Finally, 14.8333 days per clerk divided by the number of days each could have worked (18) gives the "average percentage attendance": 14.8333 / 18 ≈ 0.82407 = 82.407%
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Fartash Y.
01/18/15