The length of a new rectangular playing field is 2 yards longer than triple the width. If the perimeter of the rectangular playing field is 468 yards, what are it’s dimensions

Answer 1

Greetings! Lets solve this shall we ?

So, we must solve this problem by finding it dimensions! So let the length be equal to l = 3x + 2 and the width be w = x. The perimeter is P = 468 yards. The formula for the perimeter of a rectangle is

P = 2l + 2w

468 = 2(3x+2) + 2(x)

468 = 6x + 4 + 2x

468 = 8x + 4..............Then subtract 4 to get

464 = 8x..............Then divide 8 such that

x = width = 58 yards

Now we plug in 58 into the length such that

l = 3(58)+2

length = 174 + 2

length = 176 yards

I hope this helped!