A client is withdrawing $105.83. He would like $40 in $10 bills and the rest in the feweat number of bills and coins possible.

Answer 1

If $50 bills are allowed:

105.83

-40.00

65.83

1 $50 bill

1 $10 bill

1 $5 bill

3 quarters

1 nickel

3 pennies

Answer 2

Then 105.83 - 40 = 65.83 remains to be dispensed.

Assuming that $50 bills are not allowed, you get

3 x $20 bills = $60

1 x $5 bill = $5

3 x quarter = 0.75

1 x nickle = 0.05

3 x penny = 0.03

PLUS 4 x $10 bills