
Sam Z. answered 06/07/19
Math/Science Tutor
h=3.26m
t=.59sec
acceleration=?
3.26=a(4.82-1.56)^2+1.56
a=3.26/12.187
=.267m/s
Kimberly K.
asked 06/05/19A student estimated based on the video that the ball left my hand 1.56 meters off the ground, and after 0.59 seconds the ball reached the maximum height of 3.26 meters.Use this information to find an equation of the form h=a(t−t1)^2+h1 for the height of the ball, in meters, after tseconds.
Sam Z. answered 06/07/19
Math/Science Tutor
h=3.26m
t=.59sec
acceleration=?
3.26=a(4.82-1.56)^2+1.56
a=3.26/12.187
=.267m/s
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