b^3+9b^2+8b-30/b+3

Question

b^3+9b^2+8b-30/b+3

Answer 1

I'm assuming that (b+3) is all in the denominator, correct?

 

First, we need to factor.  To factor a cubic, you need to use either long polynomial division, or synthetic division.  I took a chance with -3 as a zero (from the denominator) and this did factor:

 

• [(b+3)(b²+6b-10)]/(b+3)
• b²+6b-10 (this does not factor, and is your final answer)

 

I'm wondering if you were supposed to do this with long division?  Regardless, your answer should be b²+6b-10 .  It would be very difficult to show those long division steps in a typed format.