If the problem is (logx)3 - (logx)2 - 6(logx) = 0 then
logx{ (logx)2 - logx - 6) = 0 Let p = logx then we have
p{ p2 - p - 6 } = 0 or p{ (p-3)(p+2) } = 0 so the roots are 0, -2 , 3 then for p
logx = 0 x = 1
logx = -2 x = .01
logx = 3 x = 1000
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