So, if I row 5 mph in a 3 mph stream, I go 8 mph downstream and 2 mph upstream. Make sense?
d = rt, so t = d/r, and the times are the same.
540/(230 + w) = 380/(230 - w)
Cross multiply!
540(230 - w) = 380(230 + w)
Solve for w for your answer. Go!
Gideon L.
asked 05/29/19So, if I row 5 mph in a 3 mph stream, I go 8 mph downstream and 2 mph upstream. Make sense?
d = rt, so t = d/r, and the times are the same.
540/(230 + w) = 380/(230 - w)
Cross multiply!
540(230 - w) = 380(230 + w)
Solve for w for your answer. Go!
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