Arthur D. answered 12/18/14
Tutor
4.9
(288)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
The diagonals of a parallelogram bisect each other.
GR+RS+SG=21
RA+AS+RS=26
AS=SG because the diagonals of a parallelogram bisect each other.
substitute
GR+RS+AS=21
RA+RS+AS=26
add the two equations
GR+RA+2RS+2AS=47
now for the third triangle...
GR+RA+AG=35 but AG=2AS because diagonals of a parallelogram bisect each other
so we have GR+RA+2AS=35
GR+RA+2RS+2AS=47
GR+RA +2AS=35
subtract the equations
0+0 +2RS+0 =12
2RS=12 (we can basically stop here because we have the answer, however...)
RS=12/2
RS=6
RS=SM (diagonals of a...)
RM=RS+SM
RM=6+6
RM=12